11131100130321 has 24 divisors (see below), whose sum is σ = 16471620732840. Its totient is φ = 7239206995200.

The previous prime is 11131100130259. The next prime is 11131100130343. The reversal of 11131100130321 is 12303100113111.

11131100130321 is a `hidden beast` number, since 1 + 1 + 1 + 311 + 0 + 0 + 1 + 30 + 321 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 125698611600 + 11005401518721 = 354540^2 + 3317439^2 .

It is not a de Polignac number, because 11131100130321 - 2⁴³ = 2335007108113 is a prime.

It is a super-2 number, since 2×11131100130321² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11131100130294 and 11131100130303.

It is not an unprimeable number, because it can be changed into a prime (11131100130361) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3940431 + ... + 6147291.

It is an arithmetic number, because the mean of its divisors is an integer number (686317530535).

Almost surely, 2^{11131100130321} is an apocalyptic number.

It is an amenable number.

11131100130321 is a deficient number, since it is larger than the sum of its proper divisors (5340520602519).

11131100130321 is a wasteful number, since it uses less digits than its factorization.

11131100130321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2220577 (or 2220574 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 11131100130321 its reverse (12303100113111), we get a palindrome (23434200243432).

The spelling of 11131100130321 in words is "eleven trillion, one hundred thirty-one billion, one hundred million, one hundred thirty thousand, three hundred twenty-one".