11131102112133 has 4 divisors (see below), whose sum is σ = 14841469482848. Its totient is φ = 7420734741420.

The previous prime is 11131102112111. The next prime is 11131102112171. The reversal of 11131102112133 is 33121120113111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11131102112133 - 2⁵ = 11131102112101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11131102112173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1855183685353 + ... + 1855183685358.

It is an arithmetic number, because the mean of its divisors is an integer number (3710367370712).

Almost surely, 2^{11131102112133} is an apocalyptic number.

It is an amenable number.

11131102112133 is a deficient number, since it is larger than the sum of its proper divisors (3710367370715).

11131102112133 is an equidigital number, since it uses as much as digits as its factorization.

11131102112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3710367370714.

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 11131102112133 its reverse (33121120113111), we get a palindrome (44252222225244).

The spelling of 11131102112133 in words is "eleven trillion, one hundred thirty-one billion, one hundred two million, one hundred twelve thousand, one hundred thirty-three".