1113111003133 has 4 divisors (see below), whose sum is σ = 1161507133728. Its totient is φ = 1064714872540.

The previous prime is 1113111003101. The next prime is 1113111003139. The reversal of 1113111003133 is 3313001113111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1113111003133 - 2⁵ = 1113111003101 is a prime.

It is a super-2 number, since 2×1113111003133² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1113111003133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113111003139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24198065263 + ... + 24198065308.

It is an arithmetic number, because the mean of its divisors is an integer number (290376783432).

Almost surely, 2^{1113111003133} is an apocalyptic number.

It is an amenable number.

1113111003133 is a deficient number, since it is larger than the sum of its proper divisors (48396130595).

1113111003133 is an equidigital number, since it uses as much as digits as its factorization.

1113111003133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48396130594.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 1113111003133 its reverse (3313001113111), we get a palindrome (4426112116244).

The spelling of 1113111003133 in words is "one trillion, one hundred thirteen billion, one hundred eleven million, three thousand, one hundred thirty-three".