Base | Representation |
---|---|
bin | 11001010011110010101000… |
… | …101010101010111000001111 |
3 | 112121010020200001211000100101 |
4 | 121103302220222222320033 |
5 | 104042210320230413403 |
6 | 1032423354345311531 |
7 | 32305653233366542 |
oct | 3123625052527017 |
9 | 477106601730311 |
10 | 111311202201103 |
11 | 325158a7846923 |
12 | 10598a344955a7 |
13 | 4a157a816b358 |
14 | 1d6b6c3192859 |
15 | cd06d6d1871d |
hex | 653ca8aaae0f |
111311202201103 has 4 divisors (see below), whose sum is σ = 111311312868720. Its totient is φ = 111311091533488.
The previous prime is 111311202201083. The next prime is 111311202201113. The reversal of 111311202201103 is 301102202113111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111311202201103 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111311202201113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53811118 + ... + 55841371.
It is an arithmetic number, because the mean of its divisors is an integer number (27827828217180).
Almost surely, 2111311202201103 is an apocalyptic number.
111311202201103 is a deficient number, since it is larger than the sum of its proper divisors (110667617).
111311202201103 is a wasteful number, since it uses less digits than its factorization.
111311202201103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110667616.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 111311202201103 its reverse (301102202113111), we get a palindrome (412413404314214).
The spelling of 111311202201103 in words is "one hundred eleven trillion, three hundred eleven billion, two hundred two million, two hundred one thousand, one hundred three".
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