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111313020131111 = 731524835892207
BaseRepresentation
bin11001010011110100010101…
…000001100001011100100111
3112121010102100202120102111102
4121103310111001201130213
5104042223031123143421
61032424255010030315
732306046256502201
oct3123642501413447
9477112322512442
10111313020131111
113251664aa37617
121059926127839b
134a15a07998596
141d6b8167b5771
15cd079171460b
hex653d15061727

111313020131111 has 4 divisors (see below), whose sum is σ = 112837856023392. Its totient is φ = 109788184238832.

The previous prime is 111313020131087. The next prime is 111313020131123. The reversal of 111313020131111 is 111131020313111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111313020131111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111313020131171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 762417946031 + ... + 762417946176.

It is an arithmetic number, because the mean of its divisors is an integer number (28209464005848).

Almost surely, 2111313020131111 is an apocalyptic number.

111313020131111 is a deficient number, since it is larger than the sum of its proper divisors (1524835892281).

111313020131111 is an equidigital number, since it uses as much as digits as its factorization.

111313020131111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1524835892280.

The product of its (nonzero) digits is 54, while the sum is 20.

Adding to 111313020131111 its reverse (111131020313111), we get a palindrome (222444040444222).

The spelling of 111313020131111 in words is "one hundred eleven trillion, three hundred thirteen billion, twenty million, one hundred thirty-one thousand, one hundred eleven".

Divisors: 1 73 1524835892207 111313020131111