Base | Representation |
---|---|
bin | 1010000111111111000011… |
… | …1111011101100101110011 |
3 | 1110102020102100220101200102 |
4 | 2201333300333131211303 |
5 | 2424342424134311201 |
6 | 35402035401143015 |
7 | 2226165566615114 |
oct | 241776077354563 |
9 | 43366370811612 |
10 | 11132303432051 |
11 | 360220208369a |
12 | 12b9621a8aa6b |
13 | 629a055a2c19 |
14 | 2a6b4092420b |
15 | 14489b86b26b |
hex | a1ff0fdd973 |
11132303432051 has 4 divisors (see below), whose sum is σ = 11133665856504. Its totient is φ = 11130941007600.
The previous prime is 11132303432009. The next prime is 11132303432093. The reversal of 11132303432051 is 15023430323111.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11132303432009) and next prime (11132303432093).
It is a cyclic number.
It is not a de Polignac number, because 11132303432051 - 210 = 11132303431027 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11132303432651) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 681199970 + ... + 681216311.
It is an arithmetic number, because the mean of its divisors is an integer number (2783416464126).
Almost surely, 211132303432051 is an apocalyptic number.
11132303432051 is a deficient number, since it is larger than the sum of its proper divisors (1362424453).
11132303432051 is an equidigital number, since it uses as much as digits as its factorization.
11132303432051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1362424452.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 11132303432051 its reverse (15023430323111), we get a palindrome (26155733755162).
The spelling of 11132303432051 in words is "eleven trillion, one hundred thirty-two billion, three hundred three million, four hundred thirty-two thousand, fifty-one".
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