Base | Representation |
---|---|
bin | 1010000111111111011011… |
… | …0000010110001111101111 |
3 | 1110102020200002212022120212 |
4 | 2201333312300112033233 |
5 | 2424343123413224403 |
6 | 35402053133533035 |
7 | 2226201152560304 |
oct | 241776660261757 |
9 | 43366602768525 |
10 | 11132400133103 |
11 | 3602251721617 |
12 | 12b964a34417b |
13 | 629a1c62cc92 |
14 | 2a6b4d6d70ab |
15 | 1448a50bd4d8 |
hex | a1ff6c163ef |
11132400133103 has 4 divisors (see below), whose sum is σ = 11491509814848. Its totient is φ = 10773290451360.
The previous prime is 11132400133051. The next prime is 11132400133159. The reversal of 11132400133103 is 30133100423111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11132400133103 - 218 = 11132399870959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11132400133403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 179554840826 + ... + 179554840887.
It is an arithmetic number, because the mean of its divisors is an integer number (2872877453712).
Almost surely, 211132400133103 is an apocalyptic number.
11132400133103 is a deficient number, since it is larger than the sum of its proper divisors (359109681745).
11132400133103 is an equidigital number, since it uses as much as digits as its factorization.
11132400133103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 359109681744.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11132400133103 its reverse (30133100423111), we get a palindrome (41265500556214).
The spelling of 11132400133103 in words is "eleven trillion, one hundred thirty-two billion, four hundred million, one hundred thirty-three thousand, one hundred three".
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