11133001113 has 16 divisors (see below), whose sum is σ = 16827209280. Its totient is φ = 6490494144.

The previous prime is 11133001111. The next prime is 11133001141. The reversal of 11133001113 is 31110033111.

11133001113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11133001113 - 2¹ = 11133001111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11133001092 and 11133001101.

It is not an unprimeable number, because it can be changed into a prime (11133001111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7511406 + ... + 7512887.

It is an arithmetic number, because the mean of its divisors is an integer number (1051700580).

Almost surely, 2^11133001113 is an apocalyptic number.

11133001113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

11133001113 is a deficient number, since it is larger than the sum of its proper divisors (5694208167).

11133001113 is a wasteful number, since it uses less digits than its factorization.

11133001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15024328.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 11133001113 its reverse (31110033111), we get a palindrome (42243034224).

The spelling of 11133001113 in words is "eleven billion, one hundred thirty-three million, one thousand, one hundred thirteen".