Base | Representation |
---|---|
bin | 10100101111001010… |
… | …00001110110110101 |
3 | 1001201212201001111121 |
4 | 22113211001312311 |
5 | 140300022014031 |
6 | 5040414503541 |
7 | 542612643163 |
oct | 122745016665 |
9 | 31655631447 |
10 | 11133001141 |
11 | 47a331a599 |
12 | 21a8504bb1 |
13 | 1085654152 |
14 | 778812233 |
15 | 4525b2011 |
hex | 297941db5 |
11133001141 has 2 divisors, whose sum is σ = 11133001142. Its totient is φ = 11133001140.
The previous prime is 11133001111. The next prime is 11133001147. The reversal of 11133001141 is 14110033111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10905624900 + 227376241 = 104430^2 + 15079^2 .
It is a cyclic number.
It is not a de Polignac number, because 11133001141 - 215 = 11132968373 is a prime.
It is a super-3 number, since 3×111330011413 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11133001147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5566500570 + 5566500571.
It is an arithmetic number, because the mean of its divisors is an integer number (5566500571).
Almost surely, 211133001141 is an apocalyptic number.
It is an amenable number.
11133001141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11133001141 is an equidigital number, since it uses as much as digits as its factorization.
11133001141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 11133001141 its reverse (14110033111), we get a palindrome (25243034252).
The spelling of 11133001141 in words is "eleven billion, one hundred thirty-three million, one thousand, one hundred forty-one".
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