11133002011013 has 4 divisors (see below), whose sum is σ = 11151045775020. Its totient is φ = 11114958247008.

The previous prime is 11133002010979. The next prime is 11133002011051. The reversal of 11133002011013 is 31011020033111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 353908389604 + 10779093621409 = 594902^2 + 3283153^2 .

It is a cyclic number.

It is not a de Polignac number, because 11133002011013 - 2¹⁰ = 11133002009989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11133002010982 and 11133002011000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11133002011513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9021881078 + ... + 9021882311.

It is an arithmetic number, because the mean of its divisors is an integer number (2787761443755).

Almost surely, 2^{11133002011013} is an apocalyptic number.

It is an amenable number.

11133002011013 is a deficient number, since it is larger than the sum of its proper divisors (18043764007).

11133002011013 is an equidigital number, since it uses as much as digits as its factorization.

11133002011013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18043764006.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11133002011013 its reverse (31011020033111), we get a palindrome (42144022044124).

The spelling of 11133002011013 in words is "eleven trillion, one hundred thirty-three billion, two million, eleven thousand, thirteen".