Base | Representation |
---|---|
bin | 10000001100110101111… |
… | …011100010100011010011 |
3 | 10221102121212212100102110 |
4 | 100030311323202203103 |
5 | 121220020120031011 |
6 | 2211235451120403 |
7 | 143301434111454 |
oct | 20146573424323 |
9 | 3842555770373 |
10 | 1113301330131 |
11 | 39a16a639211 |
12 | 15b922443103 |
13 | 80ca3722313 |
14 | 3bc53c7112b |
15 | 1de5d5c5ba6 |
hex | 10335ee28d3 |
1113301330131 has 32 divisors (see below), whose sum is σ = 1619072870400. Its totient is φ = 677772506880.
The previous prime is 1113301330117. The next prime is 1113301330159. The reversal of 1113301330131 is 1310331033111.
It is a de Polignac number, because none of the positive numbers 2k-1113301330131 is a prime.
It is a super-2 number, since 2×11133013301312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1113301330098 and 1113301330107.
It is not an unprimeable number, because it can be changed into a prime (1113301330181) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 448591 + ... + 1558151.
It is an arithmetic number, because the mean of its divisors is an integer number (50596027200).
Almost surely, 21113301330131 is an apocalyptic number.
1113301330131 is a deficient number, since it is larger than the sum of its proper divisors (505771540269).
1113301330131 is a wasteful number, since it uses less digits than its factorization.
1113301330131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1110219.
The product of its (nonzero) digits is 243, while the sum is 21.
Adding to 1113301330131 its reverse (1310331033111), we get a palindrome (2423632363242).
The spelling of 1113301330131 in words is "one trillion, one hundred thirteen billion, three hundred one million, three hundred thirty thousand, one hundred thirty-one".
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