1113310000111 has 4 divisors (see below), whose sum is σ = 1113348992392. Its totient is φ = 1113271007832.

The previous prime is 1113310000093. The next prime is 1113310000151. The reversal of 1113310000111 is 1110000133111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1113310000111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113310000091 and 1113310000100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113310000151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19453281 + ... + 19510426.

It is an arithmetic number, because the mean of its divisors is an integer number (278337248098).

Almost surely, 2^{1113310000111} is an apocalyptic number.

1113310000111 is a deficient number, since it is larger than the sum of its proper divisors (38992281).

1113310000111 is an equidigital number, since it uses as much as digits as its factorization.

1113310000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38992280.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 1113310000111 its reverse (1110000133111), we get a palindrome (2223310133222).

The spelling of 1113310000111 in words is "one trillion, one hundred thirteen billion, three hundred ten million, one hundred eleven", and thus it is an aban number.