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1113310030113 = 3413744568273
BaseRepresentation
bin10000001100110110011…
…100101110100100100001
310221102122111020100120000
4100030312130232210201
5121220024331430423
62211240401410213
7143301601055031
oct20146634564441
93842574210500
101113310030113
1139a174540686
1215b925339969
1380ca547a238
143bc550978c1
151de5e243843
hex1033672e921

1113310030113 has 10 divisors (see below), whose sum is σ = 1663092761154. Its totient is φ = 742206686688.

The previous prime is 1113310030099. The next prime is 1113310030123. The reversal of 1113310030113 is 3110300133111.

It can be written as a sum of positive squares in only one way, i.e., 1045080933264 + 68229096849 = 1022292^2 + 261207^2 .

It is not a de Polignac number, because 1113310030113 - 217 = 1113309899041 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1113310030123) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6872284056 + ... + 6872284217.

Almost surely, 21113310030113 is an apocalyptic number.

It is an amenable number.

1113310030113 is a deficient number, since it is larger than the sum of its proper divisors (549782731041).

1113310030113 is an equidigital number, since it uses as much as digits as its factorization.

1113310030113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13744568285 (or 13744568276 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 1113310030113 its reverse (3110300133111), we get a palindrome (4223610163224).

The spelling of 1113310030113 in words is "one trillion, one hundred thirteen billion, three hundred ten million, thirty thousand, one hundred thirteen".

Divisors: 1 3 9 27 81 13744568273 41233704819 123701114457 371103343371 1113310030113