Base | Representation |
---|---|
bin | 10000001100110110011… |
… | …101000010110101101101 |
3 | 10221102122111101120102211 |
4 | 100030312131002311231 |
5 | 121220024342110013 |
6 | 2211240403250421 |
7 | 143301601552051 |
oct | 20146635026555 |
9 | 3842574346384 |
10 | 1113310113133 |
11 | 39a174597a99 |
12 | 15b925379a11 |
13 | 80ca54a8c6a |
14 | 3bc550b9c61 |
15 | 1de5e25d23d |
hex | 10336742d6d |
1113310113133 has 4 divisors (see below), whose sum is σ = 1113314302720. Its totient is φ = 1113305923548.
The previous prime is 1113310113119. The next prime is 1113310113161. The reversal of 1113310113133 is 3313110133111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1113310113133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1113310113193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1667085 + ... + 2237362.
It is an arithmetic number, because the mean of its divisors is an integer number (278328575680).
Almost surely, 21113310113133 is an apocalyptic number.
It is an amenable number.
1113310113133 is a deficient number, since it is larger than the sum of its proper divisors (4189587).
1113310113133 is an equidigital number, since it uses as much as digits as its factorization.
1113310113133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4189586.
The product of its (nonzero) digits is 243, while the sum is 22.
Adding to 1113310113133 its reverse (3313110133111), we get a palindrome (4426420246244).
The spelling of 1113310113133 in words is "one trillion, one hundred thirteen billion, three hundred ten million, one hundred thirteen thousand, one hundred thirty-three".
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