Base | Representation |
---|---|
bin | 10100101111001010… |
… | …11100111100100111 |
3 | 1001201212220200201022 |
4 | 22113211130330213 |
5 | 140300034041403 |
6 | 5040421121355 |
7 | 542613614531 |
oct | 122745347447 |
9 | 31655820638 |
10 | 11133112103 |
11 | 47a33959a3 |
12 | 21a855925b |
13 | 10856927c9 |
14 | 778840851 |
15 | 4525d4d38 |
hex | 29795cf27 |
11133112103 has 4 divisors (see below), whose sum is σ = 11195308440. Its totient is φ = 11070915768.
The previous prime is 11133112061. The next prime is 11133112121. The reversal of 11133112103 is 30121133111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30121133111 = 541 ⋅55676771.
It is a cyclic number.
It is not a de Polignac number, because 11133112103 - 216 = 11133046567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11133112153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31097900 + ... + 31098257.
It is an arithmetic number, because the mean of its divisors is an integer number (2798827110).
Almost surely, 211133112103 is an apocalyptic number.
11133112103 is a deficient number, since it is larger than the sum of its proper divisors (62196337).
11133112103 is an equidigital number, since it uses as much as digits as its factorization.
11133112103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 62196336.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11133112103 its reverse (30121133111), we get a palindrome (41254245214).
The spelling of 11133112103 in words is "eleven billion, one hundred thirty-three million, one hundred twelve thousand, one hundred three".
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