11133222131113 has 4 divisors (see below), whose sum is σ = 11133537207120. Its totient is φ = 11132907055108.

The previous prime is 11133222131081. The next prime is 11133222131137. The reversal of 11133222131113 is 31113122233111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11133222131113 - 2⁵ = 11133222131081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11133222131153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157484995 + ... + 157555672.

It is an arithmetic number, because the mean of its divisors is an integer number (2783384301780).

Almost surely, 2^{11133222131113} is an apocalyptic number.

It is an amenable number.

11133222131113 is a deficient number, since it is larger than the sum of its proper divisors (315076007).

11133222131113 is an equidigital number, since it uses as much as digits as its factorization.

11133222131113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 315076006.

The product of its digits is 648, while the sum is 25.

Adding to 11133222131113 its reverse (31113122233111), we get a palindrome (42246344364224).

The spelling of 11133222131113 in words is "eleven trillion, one hundred thirty-three billion, two hundred twenty-two million, one hundred thirty-one thousand, one hundred thirteen".