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11133311113 = 19955946287
BaseRepresentation
bin10100101111001100…
…01101100010001001
31001201220021210201001
422113212031202021
5140300111423423
65040425255001
7542615403661
oct122746154211
931656253631
1011133311113
1147a3511471
1221a8634461
131085732272
147788931a1
15452623cad
hex29798d889

11133311113 has 4 divisors (see below), whose sum is σ = 11189257600. Its totient is φ = 11077364628.

The previous prime is 11133311107. The next prime is 11133311171. The reversal of 11133311113 is 31111333111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31111333111 = 231352666657.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11133311113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11133311213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27972945 + ... + 27973342.

It is an arithmetic number, because the mean of its divisors is an integer number (2797314400).

Almost surely, 211133311113 is an apocalyptic number.

It is an amenable number.

11133311113 is a deficient number, since it is larger than the sum of its proper divisors (55946487).

11133311113 is an equidigital number, since it uses as much as digits as its factorization.

11133311113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55946486.

The product of its digits is 81, while the sum is 19.

Adding to 11133311113 its reverse (31111333111), we get a palindrome (42244644224).

The spelling of 11133311113 in words is "eleven billion, one hundred thirty-three million, three hundred eleven thousand, one hundred thirteen".

Divisors: 1 199 55946287 11133311113