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1113332441241 = 3371110813747
BaseRepresentation
bin10000001100110111110…
…010001110000010011001
310221102201001101221211210
4100030313302032002121
5121220101101104431
62211242522013333
7143302262415426
oct20146762160231
93842631357753
101113332441241
1139a186158479
1215b930947249
1380ca9cc5c67
143bc5804cd4d
151de611bdd46
hex10337c8e099

1113332441241 has 4 divisors (see below), whose sum is σ = 1484443254992. Its totient is φ = 742221627492.

The previous prime is 1113332441237. The next prime is 1113332441261. The reversal of 1113332441241 is 1421442333111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1113332441241 - 22 = 1113332441237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1113332441199 and 1113332441208.

It is not an unprimeable number, because it can be changed into a prime (1113332441231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185555406871 + ... + 185555406876.

It is an arithmetic number, because the mean of its divisors is an integer number (371110813748).

Almost surely, 21113332441241 is an apocalyptic number.

It is an amenable number.

1113332441241 is a deficient number, since it is larger than the sum of its proper divisors (371110813751).

1113332441241 is an equidigital number, since it uses as much as digits as its factorization.

1113332441241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 371110813750.

The product of its digits is 6912, while the sum is 30.

Adding to 1113332441241 its reverse (1421442333111), we get a palindrome (2534774774352).

The spelling of 1113332441241 in words is "one trillion, one hundred thirteen billion, three hundred thirty-two million, four hundred forty-one thousand, two hundred forty-one".

Divisors: 1 3 371110813747 1113332441241