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11133331153 = 72140774297
BaseRepresentation
bin10100101111001100…
…10010011011010001
31001201220022211012021
422113212102123101
5140300113044103
65040425531441
7542615516260
oct122746223321
931656284167
1011133331153
1147a352552a
1221a8643b81
13108573b419
1477889a5d7
15452629bbd
hex2979926d1

11133331153 has 8 divisors (see below), whose sum is σ = 12724572672. Its totient is φ = 9542281056.

The previous prime is 11133331129. The next prime is 11133331273. The reversal of 11133331153 is 35113333111.

11133331153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11133331153 - 29 = 11133330641 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11133331553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 112701 + ... + 186997.

It is an arithmetic number, because the mean of its divisors is an integer number (1590571584).

Almost surely, 211133331153 is an apocalyptic number.

It is an amenable number.

11133331153 is a deficient number, since it is larger than the sum of its proper divisors (1591241519).

11133331153 is an equidigital number, since it uses as much as digits as its factorization.

11133331153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95711.

The product of its digits is 1215, while the sum is 25.

Adding to 11133331153 its reverse (35113333111), we get a palindrome (46246664264).

The spelling of 11133331153 in words is "eleven billion, one hundred thirty-three million, three hundred thirty-one thousand, one hundred fifty-three".

Divisors: 1 7 21407 74297 149849 520079 1590475879 11133331153