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1113414201241 = 1283278676383
BaseRepresentation
bin10000001100111100101…
…010000110111110011001
310221102220202020210110221
4100030330222012332121
5121220233013414431
62211255002240041
7143304304361656
oct20147452067631
93842822223427
101113414201241
1139a218320a21
1215b9541b6021
1380cc0c21464
143bc64c52c2d
151de6846e111
hex1033ca86f99

1113414201241 has 4 divisors (see below), whose sum is σ = 1113423005952. Its totient is φ = 1113405396532.

The previous prime is 1113414201209. The next prime is 1113414201257. The reversal of 1113414201241 is 1421024143111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1113414201241 - 25 = 1113414201209 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1113414201841) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4209865 + ... + 4466518.

It is an arithmetic number, because the mean of its divisors is an integer number (278355751488).

Almost surely, 21113414201241 is an apocalyptic number.

It is an amenable number.

1113414201241 is a deficient number, since it is larger than the sum of its proper divisors (8804711).

1113414201241 is an equidigital number, since it uses as much as digits as its factorization.

1113414201241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8804710.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1113414201241 its reverse (1421024143111), we get a palindrome (2534438344352).

The spelling of 1113414201241 in words is "one trillion, one hundred thirteen billion, four hundred fourteen million, two hundred one thousand, two hundred forty-one".

Divisors: 1 128327 8676383 1113414201241