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11134406273 = 17962203387
BaseRepresentation
bin10100101111010100…
…11000111010000001
31001201222100102222112
422113222120322001
5140300402000043
65040504545105
7542630614604
oct122752307201
931658312875
1011134406273
1147a409a261
1221a8a82195
131085a268a3
14778a9a33b
1545278d518
hex297a98e81

11134406273 has 4 divisors (see below), whose sum is σ = 11196609840. Its totient is φ = 11072202708.

The previous prime is 11134406251. The next prime is 11134406287. The reversal of 11134406273 is 37260443111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11134406273 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11134406573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31101515 + ... + 31101872.

It is an arithmetic number, because the mean of its divisors is an integer number (2799152460).

Almost surely, 211134406273 is an apocalyptic number.

It is an amenable number.

11134406273 is a deficient number, since it is larger than the sum of its proper divisors (62203567).

11134406273 is an equidigital number, since it uses as much as digits as its factorization.

11134406273 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62203566.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 11134406273 its reverse (37260443111), we get a palindrome (48394849384).

The spelling of 11134406273 in words is "eleven billion, one hundred thirty-four million, four hundred six thousand, two hundred seventy-three".

Divisors: 1 179 62203387 11134406273