Base | Representation |
---|---|
bin | 1010001000001010011000… |
… | …1011101101110001011010 |
3 | 1110102112021012222201012200 |
4 | 2202002212023231301122 |
5 | 2424420140342221104 |
6 | 35403301152351030 |
7 | 2226334121341464 |
oct | 242024613556132 |
9 | 43375235881180 |
10 | 11135343320154 |
11 | 3603522008609 |
12 | 12ba12bb45476 |
13 | 62a09b312091 |
14 | 2a6d4c551134 |
15 | 1449c868db39 |
hex | a20a62edc5a |
11135343320154 has 12 divisors (see below), whose sum is σ = 24126577193706. Its totient is φ = 3711781106712.
The previous prime is 11135343320081. The next prime is 11135343320207. The reversal of 11135343320154 is 45102334353111.
11135343320154 is a `hidden beast` number, since 1 + 1 + 1 + 3 + 53 + 433 + 20 + 154 = 666.
It can be written as a sum of positive squares in only one way, i.e., 9878417570025 + 1256925750129 = 3142995^2 + 1121127^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 309315092209 + ... + 309315092244.
Almost surely, 211135343320154 is an apocalyptic number.
11135343320154 is an abundant number, since it is smaller than the sum of its proper divisors (12991233873552).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11135343320154 is a wasteful number, since it uses less digits than its factorization.
11135343320154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 618630184461 (or 618630184458 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
Adding to 11135343320154 its reverse (45102334353111), we get a palindrome (56237677673265).
The spelling of 11135343320154 in words is "eleven trillion, one hundred thirty-five billion, three hundred forty-three million, three hundred twenty thousand, one hundred fifty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •