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1113690648119 = 7159098664017
BaseRepresentation
bin10000001101001101001…
…000101010111000110111
310221110122000102202022012
4100031031020222320313
5121221314301214434
62211342235354435
7143314202213360
oct20151510527067
93843560382265
101113690648119
1139a34a378615
1215ba108b2a1b
13810362937aa
143bc8d854b67
151de828793ce
hex1034d22ae37

1113690648119 has 4 divisors (see below), whose sum is σ = 1272789312144. Its totient is φ = 954591984096.

The previous prime is 1113690648107. The next prime is 1113690648143. The reversal of 1113690648119 is 9118460963111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1113690648119 - 232 = 1109395680823 is a prime.

It is a super-4 number, since 4×11136906481194 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1113690648019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79549332002 + ... + 79549332015.

It is an arithmetic number, because the mean of its divisors is an integer number (318197328036).

Almost surely, 21113690648119 is an apocalyptic number.

1113690648119 is a deficient number, since it is larger than the sum of its proper divisors (159098664025).

1113690648119 is an equidigital number, since it uses as much as digits as its factorization.

1113690648119 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159098664024.

The product of its (nonzero) digits is 279936, while the sum is 50.

The spelling of 1113690648119 in words is "one trillion, one hundred thirteen billion, six hundred ninety million, six hundred forty-eight thousand, one hundred nineteen".

Divisors: 1 7 159098664017 1113690648119