Base | Representation |
---|---|
bin | 1010001000011011111001… |
… | …0000001001111011101011 |
3 | 1110102222101200120200122120 |
4 | 2202012332100021323223 |
5 | 2430004301234321210 |
6 | 35405355323522323 |
7 | 2226561425344410 |
oct | 242067620117353 |
9 | 43388350520576 |
10 | 11140042104555 |
11 | 3605513390901 |
12 | 12bb0216893a3 |
13 | 62a669938790 |
14 | 2a7276604107 |
15 | 144ba0e46270 |
hex | a21be409eeb |
11140042104555 has 64 divisors (see below), whose sum is σ = 22110048780288. Its totient is φ = 4663838269440.
The previous prime is 11140042104547. The next prime is 11140042104619. The reversal of 11140042104555 is 55540124004111.
11140042104555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11140042104555 - 23 = 11140042104547 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 31957366 + ... + 32304075.
It is an arithmetic number, because the mean of its divisors is an integer number (345469512192).
Almost surely, 211140042104555 is an apocalyptic number.
11140042104555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11140042104555 is a deficient number, since it is larger than the sum of its proper divisors (10970006675733).
11140042104555 is a wasteful number, since it uses less digits than its factorization.
11140042104555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64261596.
The product of its (nonzero) digits is 16000, while the sum is 33.
Adding to 11140042104555 its reverse (55540124004111), we get a palindrome (66680166108666).
The spelling of 11140042104555 in words is "eleven trillion, one hundred forty billion, forty-two million, one hundred four thousand, five hundred fifty-five".
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