Base | Representation |
---|---|
bin | 10100110000000000… |
… | …00000001001001111 |
3 | 1001202101000021220211 |
4 | 22120000000021033 |
5 | 140303324301030 |
6 | 5041230223251 |
7 | 543030023032 |
oct | 123000001117 |
9 | 31671007824 |
10 | 11140072015 |
11 | 47a7309a96 |
12 | 21aa954b27 |
13 | 1086c5b6b7 |
14 | 779733019 |
15 | 45300c12a |
hex | 29800024f |
11140072015 has 4 divisors (see below), whose sum is σ = 13368086424. Its totient is φ = 8912057608.
The previous prime is 11140071997. The next prime is 11140072051. The reversal of 11140072015 is 51027004111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11140072015 - 215 = 11140039247 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1114007197 + ... + 1114007206.
It is an arithmetic number, because the mean of its divisors is an integer number (3342021606).
Almost surely, 211140072015 is an apocalyptic number.
11140072015 is a deficient number, since it is larger than the sum of its proper divisors (2228014409).
11140072015 is an equidigital number, since it uses as much as digits as its factorization.
11140072015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2228014408.
The product of its (nonzero) digits is 280, while the sum is 22.
Adding to 11140072015 its reverse (51027004111), we get a palindrome (62167076126).
The spelling of 11140072015 in words is "eleven billion, one hundred forty million, seventy-two thousand, fifteen".
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