Base | Representation |
---|---|
bin | 10100110000000000… |
… | …01100010110110010 |
3 | 1001202101002211112101 |
4 | 22120000030112302 |
5 | 140303332401114 |
6 | 5041231251014 |
7 | 543030321616 |
oct | 123000142662 |
9 | 31671084471 |
10 | 11140122034 |
11 | 47a7343628 |
12 | 21aa979a6a |
13 | 1086c783b2 |
14 | 779747346 |
15 | 45301bd74 |
hex | 29800c5b2 |
11140122034 has 4 divisors (see below), whose sum is σ = 16710183054. Its totient is φ = 5570061016.
The previous prime is 11140122001. The next prime is 11140122061. The reversal of 11140122034 is 43022104111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8677481409 + 2462640625 = 93153^2 + 49625^2 .
It is a super-3 number, since 3×111401220343 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2785030507 + ... + 2785030510.
Almost surely, 211140122034 is an apocalyptic number.
11140122034 is a deficient number, since it is larger than the sum of its proper divisors (5570061020).
11140122034 is an equidigital number, since it uses as much as digits as its factorization.
11140122034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5570061019.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 11140122034 its reverse (43022104111), we get a palindrome (54162226145).
The spelling of 11140122034 in words is "eleven billion, one hundred forty million, one hundred twenty-two thousand, thirty-four".
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