11140322314133 has 4 divisors (see below), whose sum is σ = 11211279781260. Its totient is φ = 11069364847008.

The previous prime is 11140322314129. The next prime is 11140322314141. The reversal of 11140322314133 is 33141322304111.

11140322314133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6857814900049 + 4282507414084 = 2618743^2 + 2069422^2 .

It is a cyclic number.

It is not a de Polignac number, because 11140322314133 - 2² = 11140322314129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11140322314096 and 11140322314105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11140322314123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35478733328 + ... + 35478733641.

It is an arithmetic number, because the mean of its divisors is an integer number (2802819945315).

Almost surely, 2^{11140322314133} is an apocalyptic number.

It is an amenable number.

11140322314133 is a deficient number, since it is larger than the sum of its proper divisors (70957467127).

11140322314133 is an equidigital number, since it uses as much as digits as its factorization.

11140322314133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70957467126.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 11140322314133 its reverse (33141322304111), we get a palindrome (44281644618244).

The spelling of 11140322314133 in words is "eleven trillion, one hundred forty billion, three hundred twenty-two million, three hundred fourteen thousand, one hundred thirty-three".