Base | Representation |
---|---|
bin | 10100110000001000… |
… | …10110011111100101 |
3 | 1001202110011012212102 |
4 | 22120010112133211 |
5 | 140304122242013 |
6 | 5041310501445 |
7 | 543042512012 |
oct | 123004263745 |
9 | 31673135772 |
10 | 11141212133 |
11 | 47a7a18637 |
12 | 21ab204885 |
13 | 108726a61c |
14 | 77994c709 |
15 | 453184d58 |
hex | 2981167e5 |
11141212133 has 4 divisors (see below), whose sum is σ = 11150398188. Its totient is φ = 11132026080.
The previous prime is 11141212111. The next prime is 11141212139. The reversal of 11141212133 is 33121214111.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6333453889 + 4807758244 = 79583^2 + 69338^2 .
It is a cyclic number.
It is not a de Polignac number, because 11141212133 - 212 = 11141208037 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11141212139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4591208 + ... + 4593633.
It is an arithmetic number, because the mean of its divisors is an integer number (2787599547).
Almost surely, 211141212133 is an apocalyptic number.
It is an amenable number.
11141212133 is a deficient number, since it is larger than the sum of its proper divisors (9186055).
11141212133 is an equidigital number, since it uses as much as digits as its factorization.
11141212133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9186054.
The product of its digits is 144, while the sum is 20.
Adding to 11141212133 its reverse (33121214111), we get a palindrome (44262426244).
The spelling of 11141212133 in words is "eleven billion, one hundred forty-one million, two hundred twelve thousand, one hundred thirty-three".
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