Base | Representation |
---|---|
bin | 10100110000001000… |
… | …11000101011101111 |
3 | 1001202110011200011122 |
4 | 22120010120223233 |
5 | 140304123033403 |
6 | 5041311011155 |
7 | 543042550115 |
oct | 123004305357 |
9 | 31673150148 |
10 | 11141221103 |
11 | 47a7a24351 |
12 | 21ab209abb |
13 | 108727172c |
14 | 779951ab5 |
15 | 453187838 |
hex | 298118aef |
11141221103 has 4 divisors (see below), whose sum is σ = 11141460720. Its totient is φ = 11140981488.
The previous prime is 11141221093. The next prime is 11141221111. The reversal of 11141221103 is 30112214111.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30112214111 = 7 ⋅4301744873.
It is a cyclic number.
It is not a de Polignac number, because 11141221103 - 216 = 11141155567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11141221123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25118 + ... + 151371.
It is an arithmetic number, because the mean of its divisors is an integer number (2785365180).
Almost surely, 211141221103 is an apocalyptic number.
11141221103 is a deficient number, since it is larger than the sum of its proper divisors (239617).
11141221103 is an equidigital number, since it uses as much as digits as its factorization.
11141221103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 239616.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 11141221103 its reverse (30112214111), we get a palindrome (41253435214).
The spelling of 11141221103 in words is "eleven billion, one hundred forty-one million, two hundred twenty-one thousand, one hundred three".
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