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11141300420234 = 25570650210117
BaseRepresentation
bin1010001000100000100101…
…0000001111111010001010
31110110002122101022202020222
42202020021100033322022
52430014340401421414
635410124233550042
72226634545013265
oct242101120177212
943402571282228
1011141300420234
113605aa96a8016
1212bb312b75322
1362a80a53a37a
142a7355793cdc
15144c2665068e
hexa220940fe8a

11141300420234 has 4 divisors (see below), whose sum is σ = 16711950630354. Its totient is φ = 5570650210116.

The previous prime is 11141300420213. The next prime is 11141300420291. The reversal of 11141300420234 is 43202400314111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 7718411909209 + 3422888511025 = 2778203^2 + 1850105^2 .

It is a super-2 number, since 2×111413004202342 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2785325105057 + ... + 2785325105060.

Almost surely, 211141300420234 is an apocalyptic number.

11141300420234 is a deficient number, since it is larger than the sum of its proper divisors (5570650210120).

11141300420234 is an equidigital number, since it uses as much as digits as its factorization.

11141300420234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5570650210119.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 11141300420234 its reverse (43202400314111), we get a palindrome (54343700734345).

The spelling of 11141300420234 in words is "eleven trillion, one hundred forty-one billion, three hundred million, four hundred twenty thousand, two hundred thirty-four".

Divisors: 1 2 5570650210117 11141300420234