Base | Representation |
---|---|
bin | 10100110000010111… |
… | …01000110101111111 |
3 | 1001202120202021010110 |
4 | 22120023220311333 |
5 | 140310114403203 |
6 | 5041415441103 |
7 | 543064656015 |
oct | 123013506577 |
9 | 31676667113 |
10 | 11143122303 |
11 | 47a9002795 |
12 | 21ab986193 |
13 | 1087788bc1 |
14 | 779cc88b5 |
15 | 453410d03 |
hex | 2982e8d7f |
11143122303 has 8 divisors (see below), whose sum is σ = 15061024048. Its totient is φ = 7326984384.
The previous prime is 11143122301. The next prime is 11143122343. The reversal of 11143122303 is 30322134111.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11143122303 - 21 = 11143122301 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11143122303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11143122301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25440700 + ... + 25441137.
It is an arithmetic number, because the mean of its divisors is an integer number (1882628006).
Almost surely, 211143122303 is an apocalyptic number.
11143122303 is a deficient number, since it is larger than the sum of its proper divisors (3917901745).
11143122303 is an equidigital number, since it uses as much as digits as its factorization.
11143122303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50881913.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 11143122303 its reverse (30322134111), we get a palindrome (41465256414).
The spelling of 11143122303 in words is "eleven billion, one hundred forty-three million, one hundred twenty-two thousand, three hundred three".
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