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11143214303 = 13857170331
BaseRepresentation
bin10100110000010111…
…11111010011011111
31001202120220221022212
422120023333103133
5140310130324203
65041421431035
7543065521154
oct123013772337
931676827285
1011143214303
1147a9065921
1221aba0b47b
1310877bba40
14779d1022b
1545342d1d8
hex2982ff4df

11143214303 has 4 divisors (see below), whose sum is σ = 12000384648. Its totient is φ = 10286043960.

The previous prime is 11143214287. The next prime is 11143214311. The reversal of 11143214303 is 30341234111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11143214303 - 24 = 11143214287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11143214323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 428585153 + ... + 428585178.

It is an arithmetic number, because the mean of its divisors is an integer number (3000096162).

Almost surely, 211143214303 is an apocalyptic number.

11143214303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11143214303 is a deficient number, since it is larger than the sum of its proper divisors (857170345).

11143214303 is an equidigital number, since it uses as much as digits as its factorization.

11143214303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 857170344.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11143214303 its reverse (30341234111), we get a palindrome (41484448414).

The spelling of 11143214303 in words is "eleven billion, one hundred forty-three million, two hundred fourteen thousand, three hundred three".

Divisors: 1 13 857170331 11143214303