Base | Representation |
---|---|
bin | 10000001101110011010… |
… | …000000001100111110111 |
3 | 10221112021120200210201102 |
4 | 100031303100001213313 |
5 | 121224122002013310 |
6 | 2211525521320315 |
7 | 143336065441142 |
oct | 20156320014767 |
9 | 3845246623642 |
10 | 1114330110455 |
11 | 39a64832a091 |
12 | 15bb6aa9609b |
13 | 811088c8283 |
14 | 3bd10751059 |
15 | 1debda8e8a5 |
hex | 103734019f7 |
1114330110455 has 4 divisors (see below), whose sum is σ = 1337196132552. Its totient is φ = 891464088360.
The previous prime is 1114330110449. The next prime is 1114330110457. The reversal of 1114330110455 is 5540110334111.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1114330110455 - 212 = 1114330106359 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1114330110457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111433011041 + ... + 111433011050.
It is an arithmetic number, because the mean of its divisors is an integer number (334299033138).
Almost surely, 21114330110455 is an apocalyptic number.
1114330110455 is a deficient number, since it is larger than the sum of its proper divisors (222866022097).
1114330110455 is an equidigital number, since it uses as much as digits as its factorization.
1114330110455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222866022096.
The product of its (nonzero) digits is 3600, while the sum is 29.
Adding to 1114330110455 its reverse (5540110334111), we get a palindrome (6654440444566).
The spelling of 1114330110455 in words is "one trillion, one hundred fourteen billion, three hundred thirty million, one hundred ten thousand, four hundred fifty-five".
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