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1114331042041 = 7180239883217
BaseRepresentation
bin10000001101110011010…
…011100101000011111001
310221112021122110010121121
4100031303103211003321
5121224122221321131
62211525553305241
7143336106401140
oct20156323450371
93845248403547
101114331042041
1139a648905a98
1215bb6b265221
1381108b632c9
143bd10914757
151debdbc5911
hex103734e50f9

1114331042041 has 8 divisors (see below), whose sum is σ = 1273529698560. Its totient is φ = 955134512448.

The previous prime is 1114331041987. The next prime is 1114331042081. The reversal of 1114331042041 is 1402401334111.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1114331042041 - 227 = 1114196824313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1114331041997 and 1114331042015.

It is not an unprimeable number, because it can be changed into a prime (1114331042081) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 820065 + ... + 1703281.

It is an arithmetic number, because the mean of its divisors is an integer number (159191212320).

Almost surely, 21114331042041 is an apocalyptic number.

It is an amenable number.

1114331042041 is a deficient number, since it is larger than the sum of its proper divisors (159198656519).

1114331042041 is an equidigital number, since it uses as much as digits as its factorization.

1114331042041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1063463.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1114331042041 its reverse (1402401334111), we get a palindrome (2516732376152).

The spelling of 1114331042041 in words is "one trillion, one hundred fourteen billion, three hundred thirty-one million, forty-two thousand, forty-one".

Divisors: 1 7 180239 883217 1261673 6182519 159190148863 1114331042041