Base | Representation |
---|---|
bin | 10000001101110011011… |
… | …111010100100010110001 |
3 | 10221112021212020111221021 |
4 | 100031303133110202301 |
5 | 121224124013320423 |
6 | 2211530143255441 |
7 | 143336144511124 |
oct | 20156337244261 |
9 | 3845255214837 |
10 | 1114334120113 |
11 | 39a64a618655 |
12 | 15bb702aa581 |
13 | 811096a0356 |
14 | 3bd110b63bb |
15 | 1debe0d295d |
hex | 103737d48b1 |
1114334120113 has 16 divisors (see below), whose sum is σ = 1197576092160. Its totient is φ = 1033060190976.
The previous prime is 1114334120111. The next prime is 1114334120117. The reversal of 1114334120113 is 3110214334111.
It is not a de Polignac number, because 1114334120113 - 21 = 1114334120111 is a prime.
It is a super-2 number, since 2×11143341201132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1114334120111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23910528 + ... + 23957086.
It is an arithmetic number, because the mean of its divisors is an integer number (74848505760).
Almost surely, 21114334120113 is an apocalyptic number.
It is an amenable number.
1114334120113 is a deficient number, since it is larger than the sum of its proper divisors (83241972047).
1114334120113 is a wasteful number, since it uses less digits than its factorization.
1114334120113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67656.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 1114334120113 its reverse (3110214334111), we get a palindrome (4224548454224).
The spelling of 1114334120113 in words is "one trillion, one hundred fourteen billion, three hundred thirty-four million, one hundred twenty thousand, one hundred thirteen".
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