11144323131301 has 4 divisors (see below), whose sum is σ = 11145853321632. Its totient is φ = 11142792940972.

The previous prime is 11144323131209. The next prime is 11144323131323. The reversal of 11144323131301 is 10313132344111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11144323131301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11144323131301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11144323131371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 765084241 + ... + 765098806.

It is an arithmetic number, because the mean of its divisors is an integer number (2786463330408).

Almost surely, 2^{11144323131301} is an apocalyptic number.

It is an amenable number.

11144323131301 is a deficient number, since it is larger than the sum of its proper divisors (1530190331).

11144323131301 is an equidigital number, since it uses as much as digits as its factorization.

11144323131301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1530190330.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 11144323131301 its reverse (10313132344111), we get a palindrome (21457455475412).

The spelling of 11144323131301 in words is "eleven trillion, one hundred forty-four billion, three hundred twenty-three million, one hundred thirty-one thousand, three hundred one".