Base | Representation |
---|---|
bin | 10100110000101111… |
… | …10100001100000111 |
3 | 1001202210202110000002 |
4 | 22120113310030013 |
5 | 140311424031003 |
6 | 5042012111515 |
7 | 543134052512 |
oct | 123027641407 |
9 | 31683673002 |
10 | 11146314503 |
11 | 47aa893075 |
12 | 21b0a6559b |
13 | 1088335b8c |
14 | 77a4b9d79 |
15 | 453841a88 |
hex | 2985f4307 |
11146314503 has 4 divisors (see below), whose sum is σ = 11801980080. Its totient is φ = 10490648928.
The previous prime is 11146314499. The next prime is 11146314511. The reversal of 11146314503 is 30541364111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11146314503 - 22 = 11146314499 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11146314203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327832763 + ... + 327832796.
It is an arithmetic number, because the mean of its divisors is an integer number (2950495020).
Almost surely, 211146314503 is an apocalyptic number.
11146314503 is a deficient number, since it is larger than the sum of its proper divisors (655665577).
11146314503 is an equidigital number, since it uses as much as digits as its factorization.
11146314503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 655665576.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 11146314503 its reverse (30541364111), we get a palindrome (41687678614).
The spelling of 11146314503 in words is "eleven billion, one hundred forty-six million, three hundred fourteen thousand, five hundred three".
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