Base | Representation |
---|---|
bin | 10000001110011101101… |
… | …000101101011010100001 |
3 | 10221121010010210010121012 |
4 | 100032131220231122201 |
5 | 121232101023134403 |
6 | 2212124243110305 |
7 | 143362522011410 |
oct | 20163550553241 |
9 | 3847103703535 |
10 | 1115041224353 |
11 | 39a98277a521 |
12 | 160129072395 |
13 | 811c0029224 |
14 | 3bd7ad7d477 |
15 | 1e011209ed8 |
hex | 1039da2d6a1 |
1115041224353 has 16 divisors (see below), whose sum is σ = 1283747512320. Its totient is φ = 948704537616.
The previous prime is 1115041224337. The next prime is 1115041224373. The reversal of 1115041224353 is 3534221405111.
It is a cyclic number.
It is not a de Polignac number, because 1115041224353 - 24 = 1115041224337 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1115041224373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 177200 + ... + 1503822.
It is an arithmetic number, because the mean of its divisors is an integer number (80234219520).
Almost surely, 21115041224353 is an apocalyptic number.
It is an amenable number.
1115041224353 is a deficient number, since it is larger than the sum of its proper divisors (168706287967).
1115041224353 is a wasteful number, since it uses less digits than its factorization.
1115041224353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1327516.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 1115041224353 its reverse (3534221405111), we get a palindrome (4649262629464).
The spelling of 1115041224353 in words is "one trillion, one hundred fifteen billion, forty-one million, two hundred twenty-four thousand, three hundred fifty-three".
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