Base | Representation |
---|---|
bin | 110011111100011101… |
… | …0000001101010011101 |
3 | 101122221010021101222201 |
4 | 1213320322001222131 |
5 | 3311423314040013 |
6 | 123125002411501 |
7 | 11026213400122 |
oct | 1477072015235 |
9 | 348833241881 |
10 | 111550143133 |
11 | 43343169640 |
12 | 19751b00b91 |
13 | a6996c7770 |
14 | 558301a749 |
15 | 2d7d2493dd |
hex | 19f8e81a9d |
111550143133 has 16 divisors (see below), whose sum is σ = 131738084352. Its totient is φ = 93118392000.
The previous prime is 111550143101. The next prime is 111550143137. The reversal of 111550143133 is 331341055111.
It is a cyclic number.
It is not a de Polignac number, because 111550143133 - 25 = 111550143101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (111550143137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2014758 + ... + 2069383.
It is an arithmetic number, because the mean of its divisors is an integer number (8233630272).
Almost surely, 2111550143133 is an apocalyptic number.
111550143133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
111550143133 is a deficient number, since it is larger than the sum of its proper divisors (20187941219).
111550143133 is a wasteful number, since it uses less digits than its factorization.
111550143133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4084356.
The product of its (nonzero) digits is 2700, while the sum is 28.
Adding to 111550143133 its reverse (331341055111), we get a palindrome (442891198244).
The spelling of 111550143133 in words is "one hundred eleven billion, five hundred fifty million, one hundred forty-three thousand, one hundred thirty-three".
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