Base | Representation |
---|---|
bin | 1010001001010100110010… |
… | …0011011111100110011010 |
3 | 1110111102211001011202011101 |
4 | 2202111030203133212122 |
5 | 2430232040444044402 |
6 | 35420403011022014 |
7 | 2230642043144443 |
oct | 242251443374632 |
9 | 43442731152141 |
10 | 11155314440602 |
11 | 3610a40201a32 |
12 | 1301b8429a90a |
13 | 62bc31a17a07 |
14 | 2a7cc4a7a2ca |
15 | 145296b02b87 |
hex | a254c8df99a |
11155314440602 has 4 divisors (see below), whose sum is σ = 16732971660906. Its totient is φ = 5577657220300.
The previous prime is 11155314440507. The next prime is 11155314440629. The reversal of 11155314440602 is 20604441355111.
11155314440602 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8155313774001 + 3000000666601 = 2855751^2 + 1732051^2 .
It is a super-2 number, since 2×111553144406022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2788828610149 + ... + 2788828610152.
Almost surely, 211155314440602 is an apocalyptic number.
11155314440602 is a deficient number, since it is larger than the sum of its proper divisors (5577657220304).
11155314440602 is an equidigital number, since it uses as much as digits as its factorization.
11155314440602 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5577657220303.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 11155314440602 its reverse (20604441355111), we get a palindrome (31759755795713).
The spelling of 11155314440602 in words is "eleven trillion, one hundred fifty-five billion, three hundred fourteen million, four hundred forty thousand, six hundred two".
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