112000120993 has 4 divisors (see below), whose sum is σ = 112001059008. Its totient is φ = 111999182980.

The previous prime is 112000120979. The next prime is 112000120997. The reversal of 112000120993 is 399021000211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 112000120993 - 2⁵ = 112000120961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112000120997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258373 + ... + 539218.

It is an arithmetic number, because the mean of its divisors is an integer number (28000264752).

Almost surely, 2^112000120993 is an apocalyptic number.

It is an amenable number.

112000120993 is a deficient number, since it is larger than the sum of its proper divisors (938015).

112000120993 is an equidigital number, since it uses as much as digits as its factorization.

112000120993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 938014.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 112000120993 in words is "one hundred twelve billion, one hundred twenty thousand, nine hundred ninety-three".