1120004431441 has 4 divisors (see below), whose sum is σ = 1280005064512. Its totient is φ = 960003798372.

The previous prime is 1120004431423. The next prime is 1120004431451. The reversal of 1120004431441 is 1441344000211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1120004431441 - 2²⁵ = 1119970877009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1120004431451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80000316525 + ... + 80000316538.

It is an arithmetic number, because the mean of its divisors is an integer number (320001266128).

Almost surely, 2^{1120004431441} is an apocalyptic number.

It is an amenable number.

1120004431441 is a deficient number, since it is larger than the sum of its proper divisors (160000633071).

1120004431441 is an equidigital number, since it uses as much as digits as its factorization.

1120004431441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160000633070.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1120004431441 its reverse (1441344000211), we get a palindrome (2561348431652).

The spelling of 1120004431441 in words is "one trillion, one hundred twenty billion, four million, four hundred thirty-one thousand, four hundred forty-one".