11200542433 has 4 divisors (see below), whose sum is σ = 11461020208. Its totient is φ = 10940064660.

The previous prime is 11200542403. The next prime is 11200542443. The reversal of 11200542433 is 33424500211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11200542433 - 2⁹ = 11200541921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11200542398 and 11200542407.

It is not an unprimeable number, because it can be changed into a prime (11200542403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130238823 + ... + 130238908.

It is an arithmetic number, because the mean of its divisors is an integer number (2865255052).

Almost surely, 2^11200542433 is an apocalyptic number.

It is an amenable number.

11200542433 is a deficient number, since it is larger than the sum of its proper divisors (260477775).

11200542433 is an equidigital number, since it uses as much as digits as its factorization.

11200542433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260477774.

The product of its (nonzero) digits is 2880, while the sum is 25.

The spelling of 11200542433 in words is "eleven billion, two hundred million, five hundred forty-two thousand, four hundred thirty-three".