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112011110110212 = 2231937178718733967
BaseRepresentation
bin11001011101111110011110…
…011011011101010000000100
3112200121011020212000201010120
4121131332132123131100010
5104140142223142011322
61034121105453021540
732410351504431525
oct3135763633352004
9480534225021116
10112011110110212
1132765710596245
12106906061848b0
134a667aa503731
141d9351c16484c
15ce39ecc7ea5c
hex65df9e6dd404

112011110110212 has 192 divisors, whose sum is σ = 282930904596480. Its totient is φ = 34369641805824.

The previous prime is 112011110110093. The next prime is 112011110110217. The reversal of 112011110110212 is 212011011110211.

It is a super-3 number, since 3×1120111101102123 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112011110110191 and 112011110110200.

It is not an unprimeable number, because it can be changed into a prime (112011110110217) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 28235720253 + ... + 28235724219.

It is an arithmetic number, because the mean of its divisors is an integer number (1473598461440).

Almost surely, 2112011110110212 is an apocalyptic number.

112011110110212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112011110110212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (141465452298240).

112011110110212 is an abundant number, since it is smaller than the sum of its proper divisors (170919794486268).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112011110110212 is a wasteful number, since it uses less digits than its factorization.

112011110110212 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7690 (or 7688 counting only the distinct ones).

The product of its (nonzero) digits is 8, while the sum is 15.

Adding to 112011110110212 its reverse (212011011110211), we get a palindrome (324022121220423).

Subtracting 112011110110212 from its reverse (212011011110211), we obtain a palindrome (99999900999999).

The spelling of 112011110110212 in words is "one hundred twelve trillion, eleven billion, one hundred ten million, one hundred ten thousand, two hundred twelve".