112013010001 has 4 divisors (see below), whose sum is σ = 117908431600. Its totient is φ = 106117588404.

The previous prime is 112013009929. The next prime is 112013010017. The reversal of 112013010001 is 100010310211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112013010001 - 2¹⁵ = 112012977233 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 112013010001.

It is not an unprimeable number, because it can be changed into a prime (112013010041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2947710771 + ... + 2947710808.

It is an arithmetic number, because the mean of its divisors is an integer number (29477107900).

Almost surely, 2^112013010001 is an apocalyptic number.

It is an amenable number.

112013010001 is a deficient number, since it is larger than the sum of its proper divisors (5895421599).

112013010001 is an equidigital number, since it uses as much as digits as its factorization.

112013010001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5895421598.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 112013010001 its reverse (100010310211), we get a palindrome (212023320212).

The spelling of 112013010001 in words is "one hundred twelve billion, thirteen million, ten thousand, one".