Base | Representation |
---|---|
bin | 11001011110000000011100… |
… | …111010010100110000100111 |
3 | 112200121100201201222112120012 |
4 | 121132000130322110300213 |
5 | 104140211044411143421 |
6 | 1034122100215200435 |
7 | 32410455212342423 |
oct | 3136003472246047 |
9 | 480540651875505 |
10 | 112013232131111 |
11 | 327665aa3a4a23 |
12 | 10690ab897611b |
13 | 4a66a580317bc |
14 | 1d9367dd03b83 |
15 | ce3ac41e695b |
hex | 65e01ce94c27 |
112013232131111 has 4 divisors (see below), whose sum is σ = 112106498770224. Its totient is φ = 111919965492000.
The previous prime is 112013232130991. The next prime is 112013232131131. The reversal of 112013232131111 is 111131232310211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112013232131111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112013232131131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46633317755 + ... + 46633320156.
It is an arithmetic number, because the mean of its divisors is an integer number (28026624692556).
Almost surely, 2112013232131111 is an apocalyptic number.
112013232131111 is a deficient number, since it is larger than the sum of its proper divisors (93266639113).
112013232131111 is an equidigital number, since it uses as much as digits as its factorization.
112013232131111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93266639112.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 112013232131111 its reverse (111131232310211), we get a palindrome (223144464441322).
The spelling of 112013232131111 in words is "one hundred twelve trillion, thirteen billion, two hundred thirty-two million, one hundred thirty-one thousand, one hundred eleven".
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