11201424201101 has 4 divisors (see below), whose sum is σ = 11201523484704. Its totient is φ = 11201324917500.

The previous prime is 11201424201091. The next prime is 11201424201229. The reversal of 11201424201101 is 10110242410211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11201424201101 is a prime.

It is a super-2 number, since 2×11201424201101² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11201424261101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49472375 + ... + 49698276.

It is an arithmetic number, because the mean of its divisors is an integer number (2800380871176).

Almost surely, 2^{11201424201101} is an apocalyptic number.

It is an amenable number.

11201424201101 is a deficient number, since it is larger than the sum of its proper divisors (99283603).

11201424201101 is an equidigital number, since it uses as much as digits as its factorization.

11201424201101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99283602.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 11201424201101 its reverse (10110242410211), we get a palindrome (21311666611312).

The spelling of 11201424201101 in words is "eleven trillion, two hundred one billion, four hundred twenty-four million, two hundred one thousand, one hundred one".