Base | Representation |
---|---|
bin | 11001011110000110110110… |
… | …010010000000010100111111 |
3 | 112200122000110101111121122000 |
4 | 121132012312102000110333 |
5 | 104140314131124021343 |
6 | 1034125153522153343 |
7 | 32411120340212016 |
oct | 3136066622002477 |
9 | 480560411447560 |
10 | 112020100220223 |
11 | 32769504241a28 |
12 | 106922b4ab2853 |
13 | 4a675b0c00260 |
14 | 1d93b32123a7d |
15 | ce3d77155ed3 |
hex | 65e1b648053f |
112020100220223 has 16 divisors (see below), whose sum is σ = 178721527417440. Its totient is φ = 68935446289152.
The previous prime is 112020100220219. The next prime is 112020100220257. The reversal of 112020100220223 is 322022001020211.
112020100220223 is a `hidden beast` number, since 1 + 1 + 20 + 201 + 0 + 0 + 220 + 223 = 666.
It is not a de Polignac number, because 112020100220223 - 22 = 112020100220219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112020100220196 and 112020100220205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112020100220293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 159572791986 + ... + 159572792687.
It is an arithmetic number, because the mean of its divisors is an integer number (11170095463590).
Almost surely, 2112020100220223 is an apocalyptic number.
112020100220223 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
112020100220223 is a deficient number, since it is larger than the sum of its proper divisors (66701427197217).
112020100220223 is a wasteful number, since it uses less digits than its factorization.
112020100220223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 319145584695 (or 319145584689 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 18.
Adding to 112020100220223 its reverse (322022001020211), we get a palindrome (434042101240434).
The spelling of 112020100220223 in words is "one hundred twelve trillion, twenty billion, one hundred million, two hundred twenty thousand, two hundred twenty-three".
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