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11202032013 = 34191073431
BaseRepresentation
bin10100110111011000…
…10111000110001101
31001220200121012001120
422123230113012031
5140420210011023
65051322231153
7544411462314
oct123354270615
931820535046
1011202032013
1148292894a7
1222076554b9
131096a43813
14783a6127b
1545869a8e3
hex29bb1718d

11202032013 has 8 divisors (see below), whose sum is σ = 15300336576. Its totient is φ = 7285874400.

The previous prime is 11202031979. The next prime is 11202032021. The reversal of 11202032013 is 31023020211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 11202032013 - 29 = 11202031501 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11202031983 and 11202032001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11202032213) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45536593 + ... + 45536838.

It is an arithmetic number, because the mean of its divisors is an integer number (1912542072).

Almost surely, 211202032013 is an apocalyptic number.

It is an amenable number.

11202032013 is a deficient number, since it is larger than the sum of its proper divisors (4098304563).

11202032013 is an equidigital number, since it uses as much as digits as its factorization.

11202032013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91073475.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11202032013 its reverse (31023020211), we get a palindrome (42225052224).

The spelling of 11202032013 in words is "eleven billion, two hundred two million, thirty-two thousand, thirteen".

Divisors: 1 3 41 123 91073431 273220293 3734010671 11202032013