Search a number
-
+
112023210041 = 819431367087
BaseRepresentation
bin110100001010100011…
…0101000100000111001
3101201011002102200210022
41220111012220200321
53313410420210131
6123243542100225
711044016401001
oct1502506504071
9351132380708
10112023210041
11435661aa826
121986441a675
13a74370c802
1455c9ba1001
152da9a4237b
hex1a151a8839

112023210041 has 4 divisors (see below), whose sum is σ = 112024659072. Its totient is φ = 112021761012.

The previous prime is 112023210029. The next prime is 112023210083. The reversal of 112023210041 is 140012320211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112023210041 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (112023210001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601601 + ... + 765486.

It is an arithmetic number, because the mean of its divisors is an integer number (28006164768).

Almost surely, 2112023210041 is an apocalyptic number.

It is an amenable number.

112023210041 is a deficient number, since it is larger than the sum of its proper divisors (1449031).

112023210041 is an equidigital number, since it uses as much as digits as its factorization.

112023210041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1449030.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 112023210041 its reverse (140012320211), we get a palindrome (252035530252).

The spelling of 112023210041 in words is "one hundred twelve billion, twenty-three million, two hundred ten thousand, forty-one".

Divisors: 1 81943 1367087 112023210041